Mathematics · 2019
JEE Main · 10 January 2019, Shift 2 · Q88
The value of cos (π)/2^2 · cos (π)/2^3 · … · · cos (π)/(2^10) · sin (π)/(2^10) is:
The value of
$$\cos \frac{\pi}{2^2} \cdot \cos \frac{\pi}{2^3} \cdot \ldots \cdot \cdot \cos \frac{\pi}{2^{10}} \cdot \sin \frac{\pi}{2^{10}}
$$
is :
Official answer
(3)
$\displaystyle \frac{1}{512}$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.