Mathematics · 2019
JEE Main · 9 April 2019, Shift 1 · Q88
The value of cos^2 10^°- cos 10^° cos 50^°+ cos^2 50^° is:
The value of
$$\cos ^2 10^{\circ}-\cos 10^{\circ} \cos 50^{\circ}+\cos ^2 50^{\circ} \text { is : }
$$
Official answer
(2)
$\displaystyle 3$/$\displaystyle 4$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.