Mathematics · 2022
JEE Main · 28 June 2022, Shift 2 · Q4
The term independent of x in the expansion of (1-x^2+3 x^3)(5/2 x^3-1/(5 x^2))^11, x ≠ 0 is:
The term independent of $\displaystyle x$ in the expansion of $\displaystyle \left(1-x^2+3 x^3\right)\left(\frac{5}{2} x^3-\frac{1}{5 x^2}\right)^{11}, x \neq 0$ is:
Official answer
(2)
$\displaystyle \frac{33}{200}$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.