Mathematics · 2022
JEE Main · 29 June 2022, Shift 1 · Q16
If the constant term in the expansion of (3 x^3-2 x^2+5/x^5)^10 is 2^k · l, where l is an odd integer, then the value of k is equal to:
If the constant term in the expansion of $\displaystyle \left(3 x^3-2 x^2+\frac{5}{x^5}\right)^{10}$ is $\displaystyle 2^k \cdot l$, where $\displaystyle l$ is an odd integer, then the value of $\displaystyle k$ is equal to :
Official answer
(4)
$\displaystyle 9$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.