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Mathematics · 2025

JEE Main · 2 April 2025, Shift 1 · Q16

The term independent of x in the expansion of (((x+1))/((x^2 / 3+1-x^1 / 3))-((x-1))/((x-x^1 / 2)))^10, x>1, is:

The term independent of $\displaystyle x$ in the expansion of $\displaystyle \left(\frac{(x+1)}{\left(x^{2 / 3}+1-x^{1 / 3}\right)}-\frac{(x-1)}{\left(x-x^{1 / 2}\right)}\right)^{10}, x>1$, is :
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.