Mathematics · 2025
JEE Main · 2 April 2025, Shift 2 · Q7
If Σ_r =0^10((10^r +1 -1)/(10^r)) ·^11 C_r +1 =(α^11-11^11)/(10^10), then α is equal to:
If $\displaystyle \sum_{\mathrm{r}=0}^{10}\left(\frac{10^{\mathrm{r}+1}-1}{10^{\mathrm{r}}}\right) \cdot{ }^{11} \mathrm{C}_{\mathrm{r}+1}=\frac{\alpha^{11}-11^{11}}{10^{10}}$, then $\displaystyle \alpha$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 20$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.