Mathematics · 2021
JEE Main · 31 August 2021, Shift 1 · Q87
The square of the distance of the point of intersection of the line (x-1)/2=(y-2)/3=(z+1)/6 and the plane 2 x-y+z=6 from the point (-1,-1,2) is \ \ \…
The square of the distance of the point of intersection of the line $\displaystyle \frac{x-1}{2}=\frac{y-2}{3}=\frac{z+1}{6}$ and the plane $\displaystyle 2 x-y+z=6$ from the point $\displaystyle (-1,-1,2)$ is \_\_\_\_.
Official answer
61
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.