Mathematics · 2026
JEE Main · 5 April 2026, Shift 1 · Q13
The square of the distance of the point P (5,6,7) from the line (x-2)/2=(y-5)/3=(z-2)/4 is equal to:
The square of the distance of the point $\displaystyle \mathrm{P}(5,6,7)$ from the line $\displaystyle \frac{x-2}{2}=\frac{y-5}{3}=\frac{z-2}{4}$ is equal to:
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 6$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.