Let the foot of perpendicular from the point (λ, 2,3) on the line (x-4)/1=(y-9)/2=(z-5)/1 be the point (1, μ, 2). Then the distance between the lines…

Let the foot of perpendicular from the point $\displaystyle (\lambda, 2,3)$ on the line $\displaystyle \frac{x-4}{1}=\frac{y-9}{2}=\frac{z-5}{1}$ be the point $\displaystyle (1, \mu, 2)$. Then the distance between the lines $\displaystyle \frac{x-1}{2}=\frac{y-2}{3}=\frac{z+4}{6}$ and $\displaystyle \frac{x-\lambda}{2}=\frac{y-\mu}{3}=\frac{z+5}{6}$ is equal to :