Mathematics · 2026
JEE Main · 6 April 2026, Shift 1 · Q16
Let a line L be perpendicular to both the lines L_1: (x+1)/3=(y+3)/5=(z+5)/7 and L_2: (x-2)/1=(y-4)/4=(z-6)/7. If θ is the acute angle between the…
Let a line L be perpendicular to both the lines
$$\mathrm{L}_1: \frac{x+1}{3}=\frac{y+3}{5}=\frac{z+5}{7} \text { and } \mathrm{L}_2: \frac{x-2}{1}=\frac{y-4}{4}=\frac{z-6}{7} .
$$
If $\displaystyle \theta$ is the acute angle between the lines L and
$$\mathrm{L}_3: \frac{x-\dfrac{8}{7}}{2}=\frac{y-\dfrac{4}{7}}{1}=\frac{z}{2} \text {, then } \tan \theta \text { is equal to: }
$$
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle \frac{5}{2} \sqrt{2}$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.