Mathematics · 2026
JEE Main · 4 April 2026, Shift 1 · Q15
The square of the distance of the point (-2,-8,6) from the line (x-1)/1=(y-1)/2=z/-1 along the line (x+5)/1=(y+5)/-1=z/2 is equal to:
The square of the distance of the point $\displaystyle (-2,-8,6)$ from the line $\displaystyle \frac{x-1}{1}=\frac{y-1}{2}=\frac{z}{-1}$ along the line $\displaystyle \frac{x+5}{1}=\frac{y+5}{-1}=\frac{z}{2}$ is equal to:
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 6$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.