Mathematics · 2016
JEE Main · 10 April 2016, Shift 1 · Q77
The solution of the differential equation (d y)/(d x)+y/2 sec x=(tan x)/(2 y), where 0 ≤ x<(π)/2, and y(0)=1, is given by:
The solution of the differential equation $\displaystyle \frac{d y}{d x}+\frac{y}{2} \sec x=\frac{\tan x}{2 y}$, where $\displaystyle 0 \leq x<\frac{\pi}{2}$, and $\displaystyle y(0)=1$, is given by :
Official answer
(3)
$\displaystyle y^2=1-\frac{x}{\sec x+\tan x}$
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JEE Main 2016 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.