Mathematics · 2016
JEE Main · 9 April 2016, Shift 1 · Q83
The shortest distance between the lines x/2=y/2=z/1 and (x+2)/-1=(y-4)/8=(z-5)/4 lies in the interval:
The shortest distance between the lines
$$\frac{x}{2}=\frac{y}{2}=\frac{z}{1} \text { and } \frac{x+2}{-1}=\frac{y-4}{8}=\frac{z-5}{4}
$$
lies in the interval :
Official answer
(3)
$\displaystyle (2,3]$
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JEE Main 2016 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.