Mathematics · 2026
JEE Main · 6 April 2026, Shift 2 · Q14
The shortest distance between the lines (x-4)/1=(y-3)/2=(z-2)/-3 and (x+2)/2=(y-6)/4=(z-5)/-5 is:
The shortest distance between the lines $\displaystyle \frac{x-4}{1}=\frac{y-3}{2}=\frac{z-2}{-3}$ and $\displaystyle \frac{x+2}{2}=\frac{y-6}{4}=\frac{z-5}{-5}$ is:
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 3 \sqrt{5}$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.