Mathematics · 2020
JEE Main · 8 January 2020, Shift 1 · Q65
The shortest distance between the lines (x-3)/3=(y-8)/-1=(z-3)/1 and (x+3)/-3=(y+7)/2=(z-6)/4 is:
The shortest distance between the lines $\displaystyle \frac{x-3}{3}=\frac{y-8}{-1}=\frac{z-3}{1}$ and $\displaystyle \frac{x+3}{-3}=\frac{y+7}{2}=\frac{z-6}{4}$ is :
Official answer
(2)
$\displaystyle 3 \sqrt{30}$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.