Mathematics · 2022
JEE Main · 30 June 2022, Shift 1 · Q2
The real part of the complex number ((1+2 i)^8 ·(1-2 i)^2)/((3+2 i) · (̅4̅-̅6̅i̅)̅) is equal to:
The real part of the complex number $\displaystyle \frac{(1+2 i)^8 \cdot(1-2 i)^2}{(3+2 i) \cdot \overline{(4-6 i)}}$ is equal to :
Official answer
(4)
$\displaystyle \frac{550}{13}$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.