Mathematics · 2021
JEE Main · 4 August 2021, Shift 2 · Q81
If z=(√ 3 -i)/2 and (z^95+i^95)^94=z^n, then the minimum positive integral value of ' n ' is \ \ \ \.
If $\displaystyle z=\frac{\sqrt{3}-i}{2}$ and $\displaystyle \left(z^{95}+i^{95}\right)^{94}=z^n$, then the minimum positive integral value of ' $\displaystyle n$ ' is \_\_\_\_.
Official answer
10
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.