Mathematics · 2025
JEE Main · 22 January 2025, Shift 1 · Q3
The product of all solutions of the equation e^5( log_e x)^2+3 =x^8, x>0, is:
The product of all solutions of the equation $\displaystyle \mathrm{e}^{5\left(\log _{\mathrm{e}} x\right)^2+3}=x^8, x>0$, is :
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle e^{8 / 5}$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.