Mathematics · 2026
JEE Main · 23 January 2026, Shift 2 · Q3
The sum of all the real solutions of the equation log_(x+3)(6 x^2+28 x+30)=5-2 log_(6 x+10)(x^2+6 x+9) is equal to
The sum of all the real solutions of the equation $\displaystyle \log _{(x+3)}\left(6 x^2+28 x+30\right)=5-2 \log _{(6 x+10)}\left(x^2+6 x+9\right)$ is equal to
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle 0$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.