If the set of all solutions of |x^2+x-9|=|x|+|x^2-9| is [α, β] ∪[γ, ∞), then ( α^2+β^2+γ^2 ) is equal to:

If the set of all solutions of $\displaystyle \left|x^2+x-9\right|=|x|+\left|x^2-9\right|$ is $\displaystyle [\alpha, \beta] \cup[\gamma, \infty)$, then ( $\displaystyle \alpha^2+\beta^2+\gamma^2$ ) is equal to: