Mathematics · 2019
JEE Main · 12 January 2019, Shift 1 · Q83
The perpendicular distance from the origin to the plane containing the two lines, (x+2)/3=(y-2)/5=(z+5)/7 and (x-1)/1=(y-4)/4=(z+4)/7, is:
The perpendicular distance from the origin to the plane containing the two lines,
$$\begin{aligned}
& \frac{x+2}{3}=\frac{y-2}{5}=\frac{z+5}{7} \text { and } \\
& \frac{x-1}{1}=\frac{y-4}{4}=\frac{z+4}{7}, \text { is : }
\end{aligned}
$$
Official answer
(3)
$\displaystyle 11 / \sqrt{6}$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.