Mathematics · 2024
JEE Main · 9 April 2024, Shift 1 · Q9
The parabola y^2=4 x divides the area of the circle x^2+y^2=5 in two parts. The area of the smaller part is equal to:
The parabola $\displaystyle y^2=4 x$ divides the area of the circle $\displaystyle x^2+y^2=5$ in two parts. The area of the smaller part is equal to:
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle \frac{2}{3}+5 \sin ^{-1}\left(\frac{2}{\sqrt{5}}\right)$
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.