Mathematics · 2026
JEE Main · 24 January 2026, Shift 2 · Q19
Let f(α) denote the area of the region in the first quadrant bounded by x=0, x=1, y^2=x and y=|α x-5|-|1-α x|+α x^2. Then (f(0)+f(1)) is equal to
Let $\displaystyle f(\alpha)$ denote the area of the region in the first quadrant bounded by $\displaystyle x=0, x=1, y^2=x$ and $\displaystyle y=|\alpha x-5|-|1-\alpha x|+\alpha x^2$. Then $\displaystyle (f(0)+f(1))$ is equal to
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle 7$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.