Mathematics · 2026
JEE Main · 22 January 2026, Shift 2 · Q19
The area of the region A ={(x, y): 4 x^2+y^2 ≤ 8. and.y^2 ≤ 4 x} is:
The area of the region $\displaystyle \mathrm{A}=\left\{(x, y): 4 x^2+y^2 \leqslant 8\right.$ and $\displaystyle \left.y^2 \leqslant 4 x\right\}$ is :
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle \pi+\frac{2}{3}$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.