Mathematics · 2021
JEE Main · 31 August 2021, Shift 2 · Q78
The number of solutions of the equation 32^tan^2 x+32^sec^2 x=81,0 ≤ x ≤ (π)/4 is:
The number of solutions of the equation $\displaystyle 32^{\tan ^2 x}+32^{\sec ^2 x}=81,0 \leq x \leq \frac{\pi}{4}$ is :
Official answer
(2)
$\displaystyle 1$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.