Let S={θ ∈[-π, π]-{ ± (π)/2}: sin θ tan θ+ tan θ= sin 2 θ}. If T= θ ∈ S Σ cos 2 θ, then T+n(S) is equal to:

Let $\displaystyle S=\left\{\theta \in[-\pi, \pi]-\left\{ \pm \frac{\pi}{2}\right\}: \sin \theta \tan \theta+\tan \theta=\sin 2 \theta\right\}$. If $\displaystyle T=\underset{\theta \in S}{\Sigma} \cos 2 \theta$, then $\displaystyle T+n(S)$ is equal to :