Mathematics · 2022
JEE Main · 29 June 2022, Shift 1 · Q25
The number of solutions of the equation 2 θ- cos^2 θ+√ 2 =0 in R is equal to \ \ \ \.
The number of solutions of the equation $\displaystyle 2 \theta-\cos ^2 \theta+\sqrt{2}=0$ in $\displaystyle \mathbf{R}$ is equal to \_\_\_\_.
Official answer
1
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.