Mathematics · 2023
JEE Main · 25 January 2023, Shift 1 · Q70
The minimum value of the function f(x)=∫_0^2 e^|x-t| d t is:
The minimum value of the function $\displaystyle f(x)=\int_0^2 e^{|x-t|} d t$ is :
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 2(e-1)$
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.