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Mathematics · 2023

JEE Main · 24 January 2023, Shift 2 · Q72

∫_((3 √ 2)/4)^((3 √ 3)/4) 48/(√(9-4 x^2)) d x is equal to

$\displaystyle \int_{\frac{3 \sqrt{2}}{4}}^{\frac{3 \sqrt{3}}{4}} \frac{48}{\sqrt{9-4 x^2}} d x$ is equal to
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.