Mathematics · 2024
JEE Main · 27 January 2024, Shift 2 · Q30
The mean and standard deviation of 15 observations were found to be 12 and 3 respectively. On rechecking it was found that an observation was read as…
The mean and standard deviation of $\displaystyle 15$ observations were found to be $\displaystyle 12$ and $\displaystyle 3$ respectively. On rechecking it was found that an observation was read as $\displaystyle 10$ in place of 12. If $\displaystyle \mu$ and $\displaystyle \sigma^2$ denote the mean and variance of the correct observations respectively, then $\displaystyle 15\left(\mu+\mu^2+\sigma^2\right)$ is equal to
$\displaystyle \_\_\_\_$.
Official answer
From NTA’s final answer key for this paper.
2521
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.