Mathematics · 2026
JEE Main · 23 January 2026, Shift 1 · Q8
Let the mean and variance of 8 numbers -10,-7,-1, x, y, 9,2,16 be 7/2 and 293/4, respectively. Then the mean of 4 numbers x, y, x+y+1,|x-y| is:
Let the mean and variance of $\displaystyle 8$ numbers $\displaystyle -10,-7,-1, x, y, 9,2,16$ be $\displaystyle \frac{7}{2}$ and $\displaystyle \frac{293}{4}$, respectively. Then the mean of $\displaystyle 4$ numbers $\displaystyle x, y, x+y+1,|x-y|$ is :
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 11$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.