Mathematics · 2026
JEE Main · 22 January 2026, Shift 2 · Q8
If the mean deviation about the median of the numbers k, 2 k, 3 k, ….., 1000 k is 500, then k^2 is equal to:
If the mean deviation about the median of the numbers $\displaystyle \mathrm{k}, 2 \mathrm{k}, 3 \mathrm{k}, \ldots . ., 1000 \mathrm{k}$ is $\displaystyle 500$ , then $\displaystyle \mathrm{k}^2$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 4$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.