The line of shortest distance between the lines (x-2)/0=(y-1)/1=z/1 and (x-3)/2=(y-5)/2=(z-1)/1 makes an angle of cos^-1(√(2/27)) with the plane P: a…

The line of shortest distance between the lines $\displaystyle \frac{x-2}{0}=\frac{y-1}{1}=\frac{z}{1}$ and $\displaystyle \frac{x-3}{2}=\frac{y-5}{2}=\frac{z-1}{1}$ makes an angle of $\displaystyle \cos ^{-1}\left(\sqrt{\frac{2}{27}}\right)$ with the plane $\displaystyle \mathrm{P}: \mathrm{a} x-y-z=0$, $\displaystyle (\mathrm{a}>0)$. If the image of the point $\displaystyle (1,1,-5)$ in the plane P is $\displaystyle (\alpha, \beta, \gamma)$, then $\displaystyle \alpha+\beta-\gamma$ is equal to \_\_\_\_.