Mathematics · 2017
JEE Main · 8 April 2017, Shift 1 · Q83
The line of intersection of the planes r ·(3 i - j + k )=1 and r ·( i +4 j -2 k )=2, is:
The line of intersection of the planes
$$\begin{aligned}
& \overrightarrow{\mathrm{r}} \cdot(3 \hat{i}-\hat{j}+\hat{k})=1 \text { and } \\
& \overrightarrow{\mathrm{r}} \cdot(\hat{i}+4 \hat{j}-2 \hat{k})=2, \text { is : }
\end{aligned}
$$
Official answer
(3)
$\displaystyle \frac{x-\dfrac{6}{13}}{2}=\frac{y-\dfrac{5}{13}}{-7}=\frac{z}{-13}$
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JEE Main 2017 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.