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Mathematics · 2013
JEE Main · 23 April 2013, Shift 1 · Q71
The least integral value α of x such that (x-5)/(x^2+5 x-14)>0, satisfies:
The least integral value $\displaystyle \alpha$ of $\displaystyle x$ such that
$\displaystyle \frac{x-5}{x^2+5 x-14}>0$, satisfies :
Official answer
(4)
$\displaystyle \alpha^2+5 \alpha-6=0$
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JEE Main 2013 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.