Mathematics · 2021
JEE Main · 16 March 2021, Shift 1 · Q76
If for x ∈(0, (π)/2), log_10 sin x+ log_10 cos x=-1 and log_10( sin x+ cos x)=1/2( log_10 n -1), n >0, then the value of n is equal to:
If for $\displaystyle x \in\left(0, \frac{\pi}{2}\right), \log _{10} \sin x+\log _{10} \cos x=-1$ and $\displaystyle \log _{10}(\sin x+\cos x)=\frac{1}{2}\left(\log _{10} \mathrm{n}-1\right), \mathrm{n}>0$, then the value of n is equal to :
Official answer
(2)
$\displaystyle 12$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.