Mathematics · 2022
JEE Main · 28 July 2022, Shift 2 · Q61
Let S={x ∈[-6,3]-{-2,2}: (|x+3|-1)/(|x|-2) ≥ 0} and T={x ∈ Z: x^2-7|x|+9 ≤ 0}. Then the number of elements in S ∩ T is:
Let $\displaystyle S=\left\{x \in[-6,3]-\{-2,2\}: \frac{|x+3|-1}{|x|-2} \geq 0\right\}$ and $\displaystyle T=\left\{x \in \mathbb{Z}: x^2-7|x|+9 \leq 0\right\}$.
Then the number of elements in $\displaystyle \mathrm{S} \cap \mathrm{T}$ is :
Official answer
(4)
$\displaystyle 3$
More from Basic Maths
- Let A={x ∈(0, π)-{(π)/2}: log_(2 / π)| sin x|+ log_(2 / π)| cos x|=2} and B={x ≥ 0: √x(√x-4)-3|√x-2|+6=0}. Then n(A ∪ B) is equal to:2025
- Let a, b, c be three distinct positive real numbers such that (2 a)^log_e a=(b c)^log_e b and b^log_e 2=a^log_e c. Then 6 a+5 b c is equal to ____.2023
- The sum of the squares of the roots of |x-2|^2+|x-2|-2=0 and the squares of the roots of x^2-2|x-3|-5=0, is2025
- The least value of |z| where z is complex number which satisfies the inequality exp (((|z|+3)(|z|-1))/(||z|+1|) log_e 2) ≥ log_√2|5 √7+9 i|, i=√-1,…2021
- The number of real roots of the equation x|x-2|+3|x-3|+1=0 is:2025
- If for x ∈(0, (π)/2), log_10 sin x+ log_10 cos x=-1 and log_10( sin x+ cos x)=1/2( log_10 n-1), n>0, then the value of n is equal to:2021
- The number of real solutions of the equation, x^2-|x|-12=0 is:2021
- The value of (0.16)^log_2.5(1/3+1/3^2+1/3^3+… to ∞) is equal to \ \ \ \.2020
JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.