Mathematics · 2022
JEE Main · 25 July 2022, Shift 1 · Q11
The general solution of the differential equation (x-y^2) d x+y(5 x+y^2) d y=0 is:
The general solution of the differential equation $\displaystyle \left(x-y^2\right) \mathrm{d} x+y\left(5 x+y^2\right) \mathrm{d} y=0$ is :
Official answer
(1)
$\displaystyle \left(y^2+x\right)^4=\mathrm{C}\left|\left(y^2+2 x\right)^3\right|$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.