Mathematics · 2024
JEE Main · 6 April 2024, Shift 1 · Q2
The function f(x)=(x^2+2 x-15)/(x^2-4 x+9), x ∈ R is
The function $\displaystyle f(x)=\frac{x^2+2 x-15}{x^2-4 x+9}, x \in \mathbb{R}$ is
Official answer
From NTA’s final answer key for this paper.
(4)
neither one-one nor onto.
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.