Mathematics · 2022
JEE Main · 28 July 2022, Shift 1 · Q16
The foot of the perpendicular from a point on the circle x^2+y^2=1, z =0 to the plane 2 x+3 y+z=6 lies on which one of the following curves?
The foot of the perpendicular from a point on the circle $\displaystyle x^2+y^2=1, \mathrm{z}=0$ to the plane $\displaystyle 2 x+3 y+z=6$ lies on which one of the following curves ?
Official answer
(2)
$\displaystyle (5 x+6 y-12)^2+4(3 x+5 y-9)^2=1, z=6-2 x-3 y$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.