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Mathematics · 2019
JEE Main · 9 January 2019, Shift 1 · Q84
The equation of the line passing through (-4, 3, 1), parallel to the plane x+2 y-z-5=0 and intersecting the line (x+1)/-3=(y-3)/2=(z-2)/-1 is:
The equation of the line passing through (-$\displaystyle 4$, $\displaystyle 3$, $\displaystyle 1$), parallel to the plane $\displaystyle x+2 y-z-5=0$ and intersecting the line $\displaystyle \frac{x+1}{-3}=\frac{y-3}{2}=\frac{z-2}{-1}$ is :
Official answer
(3)
$\displaystyle \frac{x+4}{3}=\frac{y-3}{-1}=\frac{z-1}{1}$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.