Mathematics · 2021
JEE Main · 24 February 2021, Shift 1 · Q77
The distance of the point (1,1,9) from the point of intersection of the line (x-3)/1=(y-4)/2=(z-5)/2 and the plane x+y+z=17 is:
The distance of the point $\displaystyle (1,1,9)$ from the point of intersection of the line $\displaystyle \frac{x-3}{1}=\frac{y-4}{2}=\frac{z-5}{2}$ and the plane $\displaystyle x+y+z=17$ is :
Official answer
(3)
$\displaystyle \sqrt{38}$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.