Mathematics · 2020
JEE Main · 4 September 2020, Shift 2 · Q67
The distance of the point (1,-2,3) from the plane x-y+z=5 measured parallel to the line x/2=y/3=z/-6 is:
The distance of the point $\displaystyle (1,-2,3)$ from the plane $\displaystyle x-y+z=5$ measured parallel to the line $\displaystyle \frac{x}{2}=\frac{y}{3}=\frac{z}{-6}$ is :
Official answer
(2)
$\displaystyle 1$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.