Offline paper
Mathematics · 2015
JEE Main 2015 · 2015-04-04 Offline · Q83
The distance of the point (1, 0, 2) from the point of intersection of the line (x-2)/3=(y+1)/4=(z-2)/12 and the plane x-y+z=16, is:
The distance of the point ($\displaystyle 1$, $\displaystyle 0$, $\displaystyle 2$) from the point of intersection of the line $\displaystyle \frac{x-2}{3}=\frac{y+1}{4}=\frac{z-2}{12}$ and the plane $\displaystyle x-y+z=16$, is :
Official answer
(4)
$\displaystyle 13$
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JEE Main 2015 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.