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Mathematics · 2025

JEE Main · 23 January 2025, Shift 2 · Q12

The distance of the line (x-2)/2=(y-6)/3=(z-3)/4 from the point (1,4,0) along the line x/1=(y-2)/2=(z+3)/3 is:

The distance of the line $\displaystyle \frac{x-2}{2}=\frac{y-6}{3}=\frac{z-3}{4}$ from the point $\displaystyle (1,4,0)$ along the line $\displaystyle \frac{x}{1}=\frac{y-2}{2}=\frac{z+3}{3}$ is :
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.