Mathematics · 2020
JEE Main · 8 January 2020, Shift 2 · Q63
The differential equation of the family of curves, x^2=4 b (y+ b ), b ∈ R, is:
The differential equation of the family of curves, $\displaystyle x^2=4 \mathrm{~b}(y+\mathrm{b}), \mathrm{b} \in \mathbf{R}$, is :
Official answer
(3)
$\displaystyle x\left(y^{\prime}\right)^2=x+2 y y^{\prime}$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.