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Mathematics · 2017

JEE Main · 8 April 2017, Shift 1 · Q82

The coordinates of the foot of the perpendicular from the point (1, -2, 1) on the plane containing the lines, (x+1)/6=(y-1)/7=(z-3)/8 and…

The coordinates of the foot of the perpendicular from the point ($\displaystyle 1$, -$\displaystyle 2$, $\displaystyle 1$) on the plane containing the lines, $\displaystyle \frac{x+1}{6}=\frac{y-1}{7}=\frac{z-3}{8}$ and $\displaystyle \frac{x-1}{3}=\frac{y-2}{5}=\frac{z-3}{7}$, is :
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