Mathematics · 2023
JEE Main · 31 January 2023, Shift 2 · Q62
The complex number z=(i-1)/(cos (π)/3+i sin (π)/3) is equal to:
The complex number $\displaystyle z=\frac{i-1}{\cos \dfrac{\pi}{3}+i \sin \dfrac{\pi}{3}} \quad$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle \sqrt{2}\left(\cos \frac{5 \pi}{12}+i \sin \frac{5 \pi}{12}\right)$
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.