Mathematics · 2024
JEE Main · 8 April 2024, Shift 2 · Q12
The area of the region in the first quadrant inside the circle x^2+y^2=8 and outside the parabola y^2=2 x is equal to:
The area of the region in the first quadrant inside the circle $\displaystyle x^2+y^2=8$ and outside the parabola $\displaystyle y^2=2 x$ is equal to:
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle \pi-\frac{2}{3}$
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.