Mathematics · 2019
JEE Main · 9 April 2019, Shift 1 · Q76
The area (in sq. units) of the region A ={(x, y): x^2 ≤ y ≤ x+2} is:
The area (in sq. units) of the region $\displaystyle \mathrm{A}=\left\{(x, y): x^2 \leq y \leq x+2\right\}$ is :
Official answer
(4)
$\displaystyle \frac{9}{2}$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.